m^2-6m-89=0

Solution for m^2-6m-89=0 equation:

m^2-6m-89=0

a = 1; b = -6; c = -89;
Δ = b2-4ac
Δ = -62-4·1·(-89)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-14\sqrt{2}}{2*1}=\frac{6-14\sqrt{2}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+14\sqrt{2}}{2*1}=\frac{6+14\sqrt{2}}{2}
$